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authorAlon Zakai <alonzakai@gmail.com>2017-11-30 11:12:17 -0800
committerGitHub <noreply@github.com>2017-11-30 11:12:17 -0800
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De-morgan's "and" law (#1297)
(eqz X) and (eqz Y) === eqz (X or Y) Normally de-morgan's laws apply only to boolean vars, but for the and (but not or or xor) version, it works in all cases (both sides are true iff X and Y have all zero bits).
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